Print a container with delimiters
It’s nice to skip a trailing delimiter when printing out a container.
A straightforward solution could be:
#include <iostream>
#include <vector>
int main(int argc, char* argv[]) {
int a[] = { 1, 2, 3, 4, 5 };
std::vector<int> v(a, a + 5);
for (int i = 0; i < v.size(); ++i) {
std::cout << v[i];
if (i < v.size() - 1)
std::cout << ", ";
}
std::cout << std::endl;
return 0;
}
A condition in the loop solves the problem, it’s better to iterate containers using manipulators:
#include <iostream>
#include <vector>
int main(int argc, char* argv[]) {
int a[] = { 1, 2, 3, 4, 5 };
std::vector<int> v(a, a + 5);
for (std::vector<int>::const_iterator i = v.begin(); i != v.end(); ++i) {
std::cout << *i;
if (v.end() - i > 1)
std::cout << ", ";
}
std::cout << std::endl;
return 0;
}
It’s not also great because iterators of some containers don’t support subtraction. For example, this code doesn’t compile if we use std::list instead of std::vector (the first example also fails on std::list but due to another reason). The better way is:
#include <iostream>
#include <vector>
int main(int argc, char* argv[]) {
int a[] = { 1, 2, 3, 4, 5 };
std::vector<int> v(a, a + 5);
typedef std::vector<int>::const_iterator iterator;
for (iterator i = v.begin(); i != v.end(); ++i) {
std::cout << *i;
if (std::distance<iterator>(i, v.end()) > 1)
std::cout << ", ";
}
std::cout << std::endl;
return 0;
}
The std::distance template can calculate the distance between two iterators even if they don’t support arithmetics. But for this kind of containers std::distance just iterates from one to another and the overall time of the print loop seems to be O(N^2) instead of original O(N). Also we have to use the type name twice — to declare the iterator and to instantiate std::distance. For example, Visual Studio 2008 cannot deduct the type from the parameters of std::distance.
There is another neat way allowing to use iterators (with O(N) time even for containers such as std::list), and to write beautifully and compactly:
#include <iostream>
#include <vector>
int main(int argc, char* argv[]) {
int a[] = { 1, 2, 3, 4, 5 };
std::vector<int> v(a, a + 5);
for (std::vector<int>::const_iterator i = v.begin(); i != v.end(); ++i) {
std::cout << *i;
if (i != --v.end())
std::cout << ", ";
}
std::cout << std::endl;
return 0;
}
The trick with pre-increment -- operator allows to check effectively for the last element of a container.
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